In developing an interval estimate for a population mean, a sample of 50 observations was used. the interval estimate was 19.76 â± 1.32. had the sample size been 200 instead of 50, the interval estimate would have been:

The formula for interval estimate would be: μ = M ± Z(sM)

Where: μ is estimate

M is the mean 

Z is the z value

(sM) is the standard error

μ = M ± Z(sM)

n = 200 rather than 50 (√200 = 2√50)

⇒ ME = (1/2) * 1.32 = .66

Using the formula above, plugging this in will give us: μ = 19.76 ± .66

 = 19.76  ±  .66 is the confidence interval or interval estimate

the answer is d on edge

step-by-step explanation:

(8+64)^2= 5184 < answer

step-by-step explanation:

2^3 = 8

4^3= 64

(8+64)^2 = 5184