Mathematics, 19.07.2019 22:40 faizanaj3978

Solve the equation for y. -3(5y+9)-7y=4(y-4)-1

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Answer from: maggie2018

-3(5y + 9) - 7y = 4(y - 4) - 1
-15y - 27 - 7y = 4y - 16 - 1
-15y - 7y - 4y = -16 - 1 + 27
-26y = 10
y = 10 / -26 = -5/13 answer

Answer from: lilroach4

I. (distribute the -3 to the equation inside the parentheses) -15y-27-7y=4(y-4)-1. (-3x5y=-15y, -3x9=-27).

II. (distribute the 4 to the equation inside the parentheses) -15y-27-7y=4y-16-1. (4xy=4y, 4x(-4)=-16).

III. (combine like terms, -15y and -7y, and -16 and -1) -22y-27=4y-17. (-15y-7y=-22y and -16-1=-17).

IV. (isolate the variable, add 27 to both sides) -22y=4y+10. (-17+27=10).

V. (isolate the variable, subtract 4y from both sides) -26y=10. (-22y-4y=-26y).

VI. (isolate the variable, divide 10 by -26 to get y by itself) y=-0.3846.

Hope this helps!

Answer from: Quest

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

Answer from: Quest

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Solve the equation for y. -3(5y+9)-7y=4(y-4)-1...

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