How do i get the solutions for this problem:
(x-4)^3 -(x^2) *(x-5)*(x+5)-2*(49x-6*(x^2)- 28)+(x+2)*((x^2) -2x+4) = 0
the solutions are:
x = -5
x = 0
x = 2
x = 5

i think that you should ask google for the answer to that problem because if we don't know it google does

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true