Triangle pqr has vertices p(–2, 6), q(–8, 4), and r(1, –2). it is translated according to the rule (x, y) → (x – 2, y – 16). what is the y-value of p'? the y-value of p' is

The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)

P = (-2,6)
P ' = (-4,-10) 

The answer is -10 because your teacher just wants the y coordinate of point P'