The perimeter is 110 in. the length of the rectangle is 4 times as long as the width. what is the width of the rectangle? ill make you brainliest if you showed your work or how you did it.

To start, let's define our variable, which is x. x will represent the width of the rectangle. Next, since you know that the length is 4 times as long as the width, it will be represented by 4x. Now, since you know that the perimeter of a figure is the sum of the length of all the sides of the rectangle, you can express the perimeter with this expression: 4x+4x+x+x
Then, you set the expression to the perimeter, which is 110.
4x+4x+x+x=110
Combine like terms: 10x=110
And solve for x: x=11
Now that you have solved for x, which represents the width of the rectangle, you now know that your answer is 11.

It is 198,87032,750 + 375 = 33145 so, we take the 6% and we make it a decimal (0.6) and multiply that, then that is your answer