Ineed to find two consecutive positive integers such that the square of the first is decreased by 17 equals to 4 times the second

So, is two integers, and they must be consecutive, meaning, the next one will have to be either 1 before the first or one after... anyhow.

let's say the first integer is "a".

then a consecutive integer to that one will be just 1 hop away, or say "a + 1", so there, those are the two integers.

now, we know that 



so, is a positive integer, so it can't be -3.

what's the second integer?  well is a + 1.

(-14+3/2b) - (1+8/2b) = -5 -5/2b(-10+b) + (7b-5) = 8b-15(7/2b-3) - (8+6b) = -5/2b-11(5+2b) + (2b+3/2) = 4b+ 13/2