Mathematics, 18.07.2019 15:30 Chloe1414
An insurance company crashed four cars in succession at 5 miles per hour. the cost of repair for each of the four crashes was $419419, $452452, $404404, $221221 . compute the range, sample variance, and sample standard deviation cost of repair
Answers: 1
![s^2= \frac{1}{4-1}[( 419419 - 374374)^2 + (452452-374374)^2+\\ (404404-374374)^2+ (221221-374374)^2)]\\ = 1.0828 \times 10^{10} ](/tpl/images/0104/4618/2d268.png)
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An insurance company crashed four cars in succession at 5 miles per hour. the cost of repair for eac...
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