Find a solution to the following system of equations -5x+2y=9 3x+5y=7 (1, 7) (–9, 7) (0, 1) (–1, 2)

So the best method is elimination method. This is what you do.

-5x + 2y = 9
3x + 5y = 7
You need to cancel out one variable so lets cancel out the x-value.
Multiply the top equation by 3 and multiply the bottome by 5.
Your new set of equations is.
-15x + 6y = 27
15x +25y = 35
Add both equations.
31y = 62
Divide.
y = 2
Plug in 2 into one of the equations.
3x + 5(2) = 7
3x + 10 = 7
Subtract 10
3x = -3
Divide 
x = 1
So your solution is (-1,2) I hope this helps love! :)

Oh sorry to disappoint u i got the answer wrong lol i tried
-5x+2y=9 3x+5y=7
                  -3x     -3x
                  5y=-3x+7
                  5     5    5
                  y=-3/5x + 1.4
                   so um maybe -1,2
                   i suck. 

Figure it out your self

i believe it's a.

i'm not sure on this one, most likely correct.

good luck!