Lou and jacob each sold 200 pieces of jewelry. if 20% of lou’s sales were rings, and jacob sold 35 rings, who sold more rings? how many more? use the drop-down menus to explain your answer

Lou sold more rings ( 40). He sold 5 more rings than Jacob

Step-by-step explanation:

Hi, to solve this problem we have to analyze the information given:

We have to multiply the pieces sold by Lou (200) by the percentage given in the decimal form (20% /100=0.2), to obtain the numbers of rings sold by Lou.

Mathematically speaking:

200 x 0.2 = 40 rings

40 (Lou)> 35 (Jacob)

Lou sold more rings (40 > 35). He sold 5 more rings than Jacob (40-35 =5)

the two may have that, even a breakdown is probably offered