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![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\ y^{\frac{1}{2}}\implies \sqrt[2]{y^1}\implies \sqrt{y}](/tpl/images/0103/1663/7b3d7.png)
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