Mathematics, 18.07.2019 05:50 edjiejwi
Find the equation for the line passing through the point (−1,1) ( − 1 , 1 ) and parallel to the line whose equation is y=2x+12.
Answers: 1
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 1}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 2 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-1=2[x-(-1)] \\\\\\ y-1=2(x+1)\implies y-1=2x+2\implies y=2x+3](/tpl/images/0102/9270/b6d0f.png)
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Find the equation for the line passing through the point (−1,1) ( − 1 , 1 ) and parallel to the line...
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