Akite is a quadrilateral with two pairs of adjacent, congruent sides. prove the two angles between the non-congruent sides are congruent. be sure to create and name the appropriate geometric figures. this figure does not need to be submitted.

∠ABD = ∠ACD

Step-by-step explanation:

Given : ABCD is a quadrilateral

            AB≈AC

            DB≈DC

To Prove : ∠ABD = ∠ACD

Proof : We know that  AB≈AC and  DB≈DC

Draw a line join A and D (refer attached figure)

This divides quadrilateral into two triangles named as ΔABD and ΔACD

Now , We know that

AB≈AC (given) this means AB = AC

DB≈DC(given) this means DB=DC

AD=AD(common)

So , by SSS property of congruency ΔABD and ΔACD are congruent .

( SSS property is when  all three sides in one triangle are the same length as the corresponding sides in the other)

Hence, ΔABD ≅ ΔACD

Since ΔABD ≅ ΔACD (Proved above)

⇒∠ABD = ∠ACD

Thus , Two angles between non-congruent sides are congruent.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice