Timothy leaves home for skedunk 400 miles away. after 2 hours, he has to reduce his speed by 20 mph due to rain. if he takes 1 hour for lunch and gas, and reaches skedunk 9 hours after he left home, what was his initial speed?

Step-by-step explanation:

This problem is divided in two parts. The first part of the travel takes 2 hours and x miles at a unknown speed which we are gonna call . The second part takes 6 hours, because the total hours is 9, but the driver took 1 hour for lunch and gas. Also, during the second part, the driver decreased his speed in 20, so the speed for the second part is , and the distance covered is gonna be 400-x because we know that the total distance is 400 miles.

Next, we have to use the equation of a constant movement which involves speed, distance and time.

So, the distance covered during the first part is 2s.

But, we know that

Then,

Therefore, the initial speed is

1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.