What is an equation of a parabola with the following vertex and focus? (-2,5) (-2,6)

To generate the equation of the parabola, we start with this equation:
(x -h)^2 = 4p * (y -k)
"h" and "k" are the (x, y) values of the vertex.
"p" is the difference between the focus "y-value" and the vertex y-value.
p = (5 -6) = 1
Now we put these numbers into the equation:
(x -h)^2 = 4p * (y -k)
(x --2)^2 = 4 * 1 * (y -5)
x^2 + 4x + 4 = 4y -20

If you want this to look like the typical quadratic equation:
x^2 + 4x + 24 = 4y
y = .25x^2 + x + 6

Source:
http://www.1728.org/quadratc.htm
(See section 3)

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