What is the decay factor of the exponential function represented by the table? 1/32/326

Hello mate!

this function is written in a next way:

f(x) = A(1 - r)^x

where A is the initial value, r is the decay factor.

The first thing we need to do is look at f(0)

in the table, we can see that f(0) = 6 = A(1-r)^0 = A*1

now we know that A = 6

now we got that the function is f(x) = 6(1 - r)^x

in the table, you can see that wehn x = 1, f(1) = 2, with this we can obtain the value of r.

f(1) = 6(1-r)^1 = 6(1 - r) = 2

You can use any point of the table in this step (where x is not zero, because we already used that point), i used x = 1 because the math was easier this way

6 - 6r = 2

6r = 4

r = 4/6 = 2/3

and now we know that f(x) = 6(1 - 2/3)^x

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.