Mathematics, 17.07.2019 07:20 emilystartk
R1 = {(a, b.β r2 | a > b}, the "greater than" relation, r2 = {(a, b.β r2 | a β₯ b}, the "greater than or equal to" relation, r3 = {(a, b.β r2 | a < b}, the "less than" relation, r4 = {(a, b.β r2 | a β€ b}, the "less than or equal to" relation, r5 = {(a, b.β r2 | a = b}, the "equal to" relation, r6 = {(a, b.β r2 | a β b}, the "unequal to" relation. find a. r2 β¦ r1. b. r2 β¦ r2. c. r3 β¦ r5. d. r4 β¦ r1. e. r5 β¦ r3. f ) r3 β¦ r6. g) r4 β¦ r6. h) r6 β¦ r6.
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R1 = {(a, b.β r2 | a > b}, the "greater than" relation, r2 = {(a, b.β r2 | a β₯ b}, the "greater...
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