Starting from 105 feet away, a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. the distance between the bicycle and the checkpoint is given by the equation d=|105-35t|. at what times is the bike 60 feet away from the checkpoint? a. 1.3 sec and 2.6 sec b. 1.3 sec and 4.7 sec c. 1.1 sec and 2.6 sec d. 4.7 sec and 9.4 sec

The given distance formula is:

d = | 105 – 35 t|

There are two working equations here due to the absolute symbol.

a. d = 105 – 35 t

b. d = 35 t – 105

From a:

60 = 105 – 35 t

t = 1.3 seconds

From b:

60 = 35 t – 105

t = 4.7 seconds

So the answer is:

B. 1.3 sec and 4.7 sec

the answer will be b x² +x-1

step-by-step explanation:

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.