Aregular pentagon has side length 12 cm. the perimeter of the pentagon is 60 cm and the area is 247.7 cm2. a second pentagon has side lengths equal to 18 cm. find the area of the second pentagon. round to the nearest tenth.

small pentagon is 12cm and the larger one is 18cm

ratio of sides = 12/18 = 2/3        s1/s2 

ratio of areas = (2/3)  ^  2     = 4/9 

a2 =   4/9 * 247.7 =    110.08    cm2

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

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