What are the solutions of the quadratic equation 4x^2 + 34x?

To find the solutions, set the equation equal to 0. You get . We are going to factor our things that both terms have in common, a 2, and an x. This gives you . How do you know this is true? If you distribute back out, you get the same as the original problem.

Now set these both equal to zero. 2x = 0, 2x + 17 = 0. Divide both sides by 2, you get one solultion of x = 0. For the other solution, subtract 17 from both sides; 2x = - 17. Divide by 2, x = -17/2 

Your solutions are x = {- 17/2, 0}

To check, plug these back into the original equation to see if they equal zero. 4(0)^2 + 34(0) = 0 + 0 = 0
4(- 17/2)^2 + 34(- 17/2) = 289 + (- 289) = 289 - 289 = 0

Where the white dots are is where your points should be plotted.a translation is simply just moving something from one place to another. in this case, you would move each plot point of the original shape 2 units up, and 5 units to the left.