What value is added to both sides of the equation x^2 − 8x = −10 in order to solve by completing the square? −8 16 −4 4

Let's solve your equation step-by-step.x2−8x=−10Step 1: Subtract -10 from both sides.x2−8x−(−10)=−10−(−10)x2−8x+10=0Step 2: Use quadratic formula with a=1, b=-8, c=10.x=−b±b2−4ac2ax=−(−8)±(−8)2−4(1)(10)2(1)x=8±242x=4+6 or x=4−6x=4+6 or x=4−6

X^2-8x=-10
we need to get (x-a)^2 with x^2-8x to figure it out
using (x-4)^2=x^2-8x+16 we see to add 16
x^2-8x=-10
x^2-8x+16=6
(x-4)^2=6
x-4=sqrt6
x=4+sqrt6 to solve for x

What is the diagram u didn't post that