The total amount of money in a savings account after t years is given by the function a=1000(1.023)^t . how could this function be rewritten to identify the monthly interest rate? what is the approximate monthly interest rate? drag and drop the choices into the boxes to correctly complete the table. if a value does not match, do not drag it to the table. function monthly interest rate a = 1000(1 + 0.023)^12t a = 1000(1.023^12)^t/12 a = 1000(1.023^t/12)^12t 0.23% 0.19% 0.31%

Rate of interest (r) = 0.19% monthly

Step-by-step explanation:

Given: The total amount of money in a saving account after t years.

Formula:

Now we compare this formula with with given model.

P=1000

Rate of interest annually (r) = 0.023

Time = t

We need to change into monthly interest

New rate will divide by 12

New time will multiply by 12

Function for monthly rate

Rate of interest (r) = 0.19% monthly

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph