City a and city b had two different temperatures on a particular day. on that day, four times the temperature of city a was 8° c more than 3 times the temperature of city b. the temperature of city a minus twice the temperature of city b was −3° c. what was the temperature of city a and city b on that day? your city a was 5° c, and city b was 4° c. city a was 3° c, and city b was −1° c. city a was 8° c, and city b was −3° c. city a was 5° c, and city b was −5° c.

City A = x

City B = y

1st equation: 4x-8 =3y

 2nd equation: x-2y = -3 , rewrite as x = 2y-3

replace x in eq. 1 with equation 2

4(2y-3) -8 =3y

8y-12-8=3y

8y-20 = 3y

-20 = -5y

y = -20/-5 = 4

x = 2y-3 = 2(4)-3 = 5

City A was 5° C, and City B was 4° C. 

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq