Y=2x^2-x-10 write in intercept form

Y-intercept:  Let x = 0 and solve for y.  Then y =2(0)^2 -(0) - 10 = -10.  The y-intercept is (0,-1).

x-intercept:  Let y = 0 and solve for x.
Then 0 = 2x^2 - x - 10.  a=2, b= -1 and c = -10.
                 -(-1) plus or minus  sqrt[ (-1)^2 - 4(2)(-10)
Then x =
                               2(2)
                  1 plus or minus sqrt(81)        1 plus or minus 9
          x = =
                                      4                                     4

Calculate the 2 x-values.  Let's call them "a" and "b."  Then the x-intercepts (there are 2) are

(a, 0) and (b, 0)

9.8? i'm not really sure