A5 in by 7in photograph is surrounded by a frame of uniform width the area of the frame equals the area of the photograph find the width of the frame

Let x be the width of the frame. 
Area of the picture is 5*7 = 35 sq in

Area of the frame given as the same, frame = 35 sq in also

Therefore the total area (picture & frame) will be 70 sq in

A simple equation would be made and it will look like this: (7+2x) * (5+2x) = 70

Using the FOIL method
35 + 14x + 10x + 4x^2 = 70
4x^2 + 24x + 35 - 70 = 0; subtract 70 from both sides:
4x^2 + 24x - 35 = 0

unluckily this will not factor easily, so we should use the quadratic equation:
where: a = 4; b = 24; c = -35
 x = -b sqrt b^2 – 4*a*c divided by 2 * a

  x = -24 ± sqrt 24^2 -4*4*(-35) divided by 2*4

 x = -24 ±sqrt 576 - -(560) divided by 8

 x = -24 ± sqrt 576 + 560 divided by 8

 x = -24 ± sqrt1136  divided by 8

 x = -24 + 33.7046 divided by 8
x =   9.7046 divided by 8
x =1.213 inches is the answer

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )