Mathematics, 30.01.2020 13:04 hectorgonzalejr333

Does each function describe exponential growth or decay?

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growth decay
y=100(1−12)^t

y=0.1(1.25)^t

y=((1−0.03)12)^2t

y=426(0.98)^t

y=2050(12)^t

Answers: 2

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A function from a set to a set is a relation that assigns to each element in the set exactly one element in the set . The set is the domain (also called the set of inputs) of the function and the set contains the range (also called the set of outputs).

$We \ denote \ the \ \mathbf{exponential \ function} \ f \ with \ base \ a \ as: \\ \\ f(x)=a^x \\ \\ where \ a0, \ a\neq 1, \ and \ x \ is \ any \ real \ number$ .

1. It isn't an exponential function.

We have the following equation:

y=100(1-12)^t

That can be written as:

y=100(-11)^t

Recall that the definition of exponential functions establishes that:

$We \ denote \ the \ \mathbf{exponential \ function} \ f \ with \ base \ a \ as: \\ \\ f(x)=a^x \\ \\ where \ a0, \ a\neq 1, \ and \ x \ is \ any \ real \ number$ .

That is:

$a \ \mathbf{must} \ be \ greater \ than \ 1$

In this problem, a=-11 , therefore this is not an exponential function.

2. Growth.

The function:

y=0.1(1.25)^t

is an exponential function because is a function of the form $f(t)=ka^t \\ \\ where \ a0 \ and \ k \ constant$

So $k=0.1 \ and \ a=1.25$ . Since $a \ is \ greater \ than \ 1$ and being raised to the power of , the function increases. This means that increases as increases as illustrated in Figure 1. This represents a growth.

3. Growth.

The function:

$y=((1-0.03)12)^{2t}$ can be written as:

$y=11.64^{2t}$

and is an exponential function because is a function of the form $f(t)=a^{bt} \\ \\ where \ a0 \ and \ b \ constant$

So $a=11.64 \ and \ b=2$ . Since $a \ is \ greater \ than \ 1$ and being raised to the power of , the function increases. As in the previous exercise, this means that increases as increases as illustrated in Figure 2. This represents a growth.

4. Decay.

The function:

y=426(0.98)^t

is an exponential function because is a function of the form $f(t)=ka^t \\ \\ where \ a0 \ and \ k \ constant$

So $k=426 \ and \ a=0.98$ . Since $a \ is \ less \ than \ 1$ and being raised to the power of , the function decreases. Here this means that decreases as increases as illustrated in Figure 3. This represents a decay.

5. Growth.

The function:

y=2050(12)^t

is an exponential function because is a function of the form $f(t)=ka^t \\ \\ where \ a0 \ and \ k \ constant$

So $k=2050 \ and \ a=12$ . Since $a \ is \ greater \ than \ 1$ and being raised to the power of , the function increases. So in this function also increases as increases as illustrated in Figure 4. This represents a growth.

Does each function describe exponential growth or decay? drag and drop the equations into the boxes

Answer from: klaw3126

1. isn't an exponential function

2. growths

3. growths

4. decay

5. growths

Step-by-step explanation:

The exponential functions has the form: y = k1*k2^(k3*t), where k1, k2 and k3 are a constants, and k2>0. Graph of exponential functions always decrease or always increase. To know if a function growths or decay just evaluate the function in 2 points, for example t = 0 and t = 1, and compare their results.

y = 100*(1−12)^x = 100*(−11)^x

Since (-11) is negative, then y is not an exponential function

y(0) = 0.1*(1.25)^(0) = 0.1

y(1) = 0.1*(1.25)^(1) = 0.125

y(1) > y(0) -> growths

y(0) =((1−0.03)12)^2(0) = 1

y(0) =((1−0.03)12)^2(1) = 135.4896

y(1) > y(0) -> growths

y(0) = 426(0.98)^(0) = 426

y(1) = 426(0.98)^(1) = 417.48

y(1) < y(0) -> decay

y(0) = 2050(12)^(0) = 2050

y(1) = 2050(12)^(1) = 24600

y(1) > y(0) -> growths

Answer from: Quest

lol

step-by-step explanation:

Answer from: Quest

konichiwa~! my name is zalgo and i am here to answer your anime-related question today. more than likely, kirishima would kill izuku, marry mino and kiss momo. all of this would be my opinion by the way. (and i am also a weeb lol)

i hope this you! : d

stay and stay proud! " - zalgo

(and do you think you can mark me as brainliest? i'd greatly appreciate it! arigato~! )

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