Suppose you had d dollars in your bank account. you spent $22 but have at least $28 left. how much money did you have initially? write and solve an inequality that represents this situation. a) d + 22 ≤ 28; d ≤ 72 b) d – 22 > 28; d > 50 c) d + 22 ≥ 28; d ≥ 72 d) d – 22 ≥ 28; d ≥ 50

D) d – 22 ≥ 28;d ≥ 50

Step-by-step explanation:

Let d represents the initial money ( in dollars ) in the account,

So, after spending $ 22 the remaining amount = initial amount - $ 22 = (d-22) dollars,

According to the question,

The remaining amount ≥ $ 28

⇒ d - 22  ≥ 28

Adding 22 on both sides, ( additive property of inequality ),

⇒ d  ≥ 50

Hence, the required inequality and its solution would be,

d - 22  ≥ 28; d  ≥ 50

Option 'D' is correct.

here is the

mark brainliest pl

only 10/60 isn't equivalent

hope this : )