Acylindrical metal pipe has a diameter of 8.4 millimeters and a height of 10 millimeters. a hole cut out of the center has a diameter of 6 millimeters. what is the volume of metal in the pipe? use 3.14 for π and round the answer to the nearest tenth of a cubic millimeter. mm3

271.3 mm^3

Step-by-step explanation:

Volume of a cylinder = πr^2h

To find the answer, we need to find the difference between the large cylindrical and small cylindrical  pipes.

V = π h (R^2 – r^2)

Given: h= 10, R is outer radius = 8.4/2 = 4.2, r is inner radius = 6/2 = 3

V = π (10) (4.2^2 – 3^2)

V= 3.14*10(17.64 - 9)

V = 31.4(8.64)

V = 271.3 mm^3

The volume of metal in the pipe 271.3 mm^3

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step-by-step explanation:

the orientation of the parabolas can easily be found by analysing the power of x and y and their signs. if x is squared , parabola opens up and also if its coefficient is negative it opens down. if y is squared , the parabola opens right and also if its coefficient is negative it opens left. however in order to do the above analysis our equation must be in standard form .

our parabola is

which is not standard form of any parabola . hence we square on both hand side and convert it into standard form.

hence we see that x is squared and its coefficient is non negative . there for it opens up.