Given: △ABC with a2 + b2 = c2 and right △DEF constructed with legs a and b and hypotenuse n
Prove: △ABC is a right triangle.
Complete the missing parts of the paragraph proof.
Proof:
We are given a2 + b2 = c2 for △ABC and right
△DEF constructed with legs a and b and hypotenuse n. Since △DEF is a right triangle, we know that a2 + b2 = n2 because of the
. By substitution, c2 = n2 Using the square root property and the principle root, we can take the square root of both sides to get
c = n. By
, triangles ABC and DEF are congruent. Since it is given that
∠F is a right angle, then ∠ is also a right angle by CPCTC. Therefore, △ABC is a right triangle by

last one.

step-by-step explanation:

last one.

generally speaking, the others follow some sort of pattern that correlates to either linear (looks like a straight line) or sinusoidal (looks like an s).

the last one is just a random cloud of points that doesn't correlate to any particular known order.

move it to the other side

step-by-step explanation:

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.