Given: angle, A, C, E, \cong, angle, A, C, F, comma∠ACE≅∠ACF, angle, E, C, B, \cong, angle, F, C, D∠ECB≅∠FCD and start overline, B, C, end overline, \cong, start overline, D, C, end overline, .
BC ≅
DC .
Prove: start overline, A, B, end overline, \cong, start overline, A, D, end overline
AB ≅
AD .

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step-by-step explanation:

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.