Solve: common factors of polynomials
factor: 8x^2 + 12x
a.4x(2x + 3)
b.8x(x + 3)
c.8x(x + 4)
d.4x^2(2x + 3)
factor. 20mn – 30m
a.2m – 3
b.10m(2n – 3)
c.10mn(2m + 3n)
d.10n(2m – 3)
factor. 15x3 – 12x
a.15x^3 – 10x
b.3x(5x^2 – 4)
c.2x(7x^2 – 5)
d. x(15x^2 – 12)
factor. 12x^2y – 3x^2y^2 – 15xy
a.3(12x^2y – xy – 15xy)
b.3(4xy – x^2y – 15xy)
c.3xy(4x – xy – 5)
d.3x^2y^2(4xy – xy – 5)
factor. 24w^2x^6 – 8wx^3
a.4wx^2(6wx^4 – 2x)
b.6wx^2(4wx^3 – 1.5x)
c.6wx(4wx^4 – x^2)
d.8wx^3(3wx^3 – 1)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

nada

step-by-step explanation:

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.