Find two consecutive integers whose sum is 73. which of the following equations could be used to solve the problem? a: 2x = 73 b: 2x + 1 = 73 c; 2x + 2 = 73 d: x2 + 1= 73

b: 2x + 1 = 73

Step-by-step explanation:

Let x be the smaller integer,

Then the larger integer consecutive to x is x + 1,

Sum of these integers = x + x + 1 = 2x + 1

According to the question,

The sum is 73

⇒ 2x + 1 = 73

Which is the required equation that could be used to solve the problem.

Option 'b' is correct.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.