When water freezes, its volume increases by 9.05% (that is, δv/v0 = 9.05 10-2). what force per unit area is water capable of exerting on a container when it freezes? (the bulk modulus of water is 2.2 109 n/m2. enter the magnitude

Given:
K = 2.2 x 10⁹ N/m², the bulk modulus of water
ε = δV/V₀ = 9.05 x 10⁻², the dilatation (volumetric strain)

Let the pressure created by the ice due to volumetric expansion be P.
By definition,

Therefore
P = (9.05 x 10⁻²) * (2.2 x 10⁹ N/m²) = 1.99 x 10⁸ Pa = 199 MPa
The pressure is 199 MPa or 1.99 x 10⁸ Pa
Note that 1 Pa = 1 N/m²

  1.99 x 10⁸ 

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm