The difference of a given month's rainfall from the average monthly rainfall is called the deviation. what is the deviation for each month shown? average monthly rainfall 3.6 given month may 2 3/5; june 7/8; july 4 1/4

Deviation:

may : 1

june: 0.875

july: 0.65

Step-by-step explanation:

It's given that the difference of a given month's rainfall from the average monthly rainfall is called the deviation .

To find : deviation for each month: may 2 3/5; june 7/8; July 4 1/4:

Solution :

Average monthly rainfall = 3.6

Rainfall in may = = 2.6

Deviation = Average monthly rainfall -  month's rainfall ( may ) = 3.6 - 2.6 = 1

Rainfall in june = 3.6 - 0.875 =

Deviation = Average monthly rainfall - month's rainfall ( june ) = 0.875

Rainfall in july =

Deviation = Average monthly rainfall - month's rainfall ( july ) = 4.25 - 3.6 = 0.65

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

is there supposed to be a diagram or a graph for this one? ?

step-by-step explanation: