The product of two consecutive even positive integers is 10 more than seven times the larger . find the integers?

2 consecutive even numbersx and x + 2

x(x + 2) = 7(x + 2) + 10
x^2 + 2x = 7x + 14 + 10
x^2 + 2x = 7x + 24
x^2 + 2x - 7x - 24 = 0
x^2 - 5x - 24 = 0
(x - 8)(x + 3) = 0

x - 8 = 0
x = 8

x + 3 = 0
x = -3...not this one because it is negative

x = 8
x + 2 = 8 + 2 = 10

so ur 2 consecutive even numbers are 8 and 10