In a experiment investigating the growth of spores in varying soil conditions a certain spore colony grew an average of 3 times larger during each 24 hours period. if the colony contained 50 spores at the beginning of the experiment how many spores were there at the end of the 4th day?

Given that the certain type of spore colony having 50 spores and a rate of growth of 3 times in 24 hour or one day period, it would grow to (3 times 50) 150 spores at the end of the first day, (3 times 150) 450 in the 2nd day, (3 times 450) 1350 in the third day, and (3 times 1350) 4050 spores at the end of the fourth day.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube