Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). the zero has a multiplicity of 1. the zero −2 has a multiplicity .

From the given function, f(x) = (x − 3)2(x + 2)2(x − 1);

The function f(x) = (x − 3)²(x + 2)²(x − 1) given can be expanded so that we have;

Hence, the zeros of the function f(x) are;

We can conclude that the zero 1 has a multiplicity of 1 and the zero -2 has a multiplicity of 2.

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we have

we know that

The zero of the function is  the value of x when the value of the function is equal to zero

rewrite the function

The zero's of the function are

so

------> has a multiplicity of

------> has a multiplicity of

------> has a multiplicity of

therefore

the answer is

The zero has a multiplicity of

The zero has a multiplicity of

f is the midpoint of