Find the area of a trapezoid with bases of 8 and 16 and a height of 10. a)1,280 sq. units b) 240 sq. units c)120 sq. units

A=[(a+b)/2]h
  =[(8+10)/2]10
  = 120

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !