Find the volume of the solid that lies under the hyperbolic paraboloid z = 4 + x 2 − y 2 and and above the square r = [−1, 1] × [0, 2].

The volume of the solid under the hyperbolic paraboloid and above the square r = [−1, 1] × [0, 2] is

The question is asking us to find the volume bounded by the following surfaces

To do this, we have to evaluate the triple integral

First, we integrate with respect to

Next, we integrate with respect to

Finally, we integrate with respect to

The volume of the solid is

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38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

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the answer is 96 degrees

step-by-step explanation:

you have to realize that a line equals 180 degrees