Bella is planning to write in a journal. some pages will have one journal entry on them, and other pages will have two journal entries on them. if bella wants to make 10 entries, how many different ways can she write them in her journal?

 6 ways

Step-by-step explanation:

Given : Bella is planning to write in a journal.

Some pages will have one journal entry on them, and other pages will have two journal entries on them.

Total required entries to make = 10

We can write 10 =10(1)+0

i.e. she can write one entry one journal entry on each page. → Way 1

10=8(1)+2(1)

i.e.  she can write one entry one journal entry per page for 8 pages and 2 journal entries on one page .→ Way 2

10=6+4 = 6(1)+2(2)

i.e.  she can write one entry one journal entry per page for 6 pages and 2 journal entries on 2 pages . → Way 3

10=4+6 = 4(1)+2(3)

i.e.  she can write one entry one journal entry per page for 4 pages and 2 journal entries on 3 pages .→ Way 4

10=2+8 = 2(1)+2(4)

i.e.  she can write one entry one journal entry per page for 2 pages and 2 journal entries on 4 pages .→ Way 5

10=0+10= 0+ 2(5)

i.e.  she can write 2 journal entries on 5 pages . → Way 6

Hence, the total number of ways she can write them in her journal = 6

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.