Acell phone service provider offers two plans. plan a includes a fee of $25 per month and charges $0.25 for every call. plan b includes a fee of $40 per month and offers unlimited calls. for what number of phone calls is the cost of plan b less than the cost of plan a?

This problem is a classic algebra problem.  Let's use our variables to create some equations.

The total cost of Plan A is mx+b, where b is the inital monthly cost of the plan and m is the rate charged per call.  x is the number of phone calls received in the month.  With this in mind, we know that the total cost of one month of Plan A is f(x)=.25x+25

The total cost of Plan B is simpler.  It's just $40.

Now we need to figure out the number x that will make Plan B<Plan A.

40<.25x+25

x=60

Therefore, Plan B costs less than Plan A after 60 phone calls have been made.