Bis between a and c. if ab=2x-8 and bc=x+17 and ac= 39. solve for x. and find the length for ab and bc.

Ok, so you know that AB + BC = AC, so you can identify the equation by identifying all of the segment values, as shown below,
AB= 2x-8            AB  +  BC  = AC, therefore
BC= x+17          2x-8 + x+17 = 39
AC=39

So, simply solve the equation algebraically, first by combining all of the like terms, and you should get 3x + 9 = 39

You can subtract both sides by 9, leaving you with 3x=30
Now you can isolate "x" by dividing both sides by 3, leaving "x" to equal 10.

Now that you know the "x" value (10), you can now plug in all of the "x" terms with 10, like so:

AB= 2(10)-8 = 12

BC= 10+17 = 27

Adding both 12 and 27 will give you 39, confirming both the "x" value being 10 and the correct length of the segments AB and BC.

If you have anymore questions, please let me know.

2(10 - 13x) + 9x = -34x + 6020 - 26x + 9x = -34x + distributive property-17x = -34x + subtraction property (subtracted 20 from both sides)17x = addition property (added 34x to both sides)x = 40/ division property (divided both sides by 17)