What is the sqrt of 4x^2/3y. ive seen it broken down as a problem on here a lot but there's parts that people dont explain how they get.

First deal withe the numerator 4 x^2 
square root of 4 is 2 and square root of x^2 = x
so square root of 4x^2  is 2x

as for the 3y  we can write it as √(3y)  

so answer is 2x / √(3y)

1.17+3.99a. you combine the terms with a to create 3.99 and the 1.17 stays because it has no like terms or a variable