Assuba driver swam 96 feet beneath the surface of the lake he then climbs up 49 feet what is his depth now

47 feet

Step-by-step explanation:

Scuba diver initially swam to 96 feet below surface of lake

also he climbed 49 feet so in totally he is at a depth of

=96-49

=47 feet

Hence he is at a depth of 47 feet from the surface of lake

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

where is the gragh

step-by-step explanation: