Mathematics, 10.07.2019 01:50 taynalizcaamanoxewm0

An implicit equation for the plane passing through the point (-1,-4,5) that is perpendicular to the line l(t) = < 1+2t,1+t,5+3t> is

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Answer from: mcfancei

Write the equation of a line that passes through
(2,-4) and is parallel to y = 4x - 6y = 4x - 12Write the equation of a line that passes through (-6,4) and is perpendicular to y = -3x +5y = 1/3 x + 6Write the equation of a line that passes through
(4,7) and is parallel to y = 5x +3y = 5x - 13Write the equation of a line that that passes through (3, -7) and is perpendicular to the line
y = -1/5 x + 1y = 5x -22Write the equation of a line that is parallel to the line x = 5.x = a, where a is any number except 5Write an equation of a line that is perpendicular to the line x = 5.y = a, where a is any number.Write an equation of a line that is parallel to the lines y = 7.y = a, where a is any number except 7.Write an equation of a line that is perpendicular to the line y = 7.x = a, where a is any number.What is the slope of a line parallel to the line
3x + 8y = 17.-3/8What is the slope of a line perpendicular to the line 4x - 5y = -18-5/4Write the equation of a line that passes through the point (1, 6) and is parallel to the line
2x + 9y = 11y = -2/9 x + 56/9Write the equation of a line that passes through the point (-3, 5) and is perpendicular to the line
2x + 9y = 11y = 9/2 x + 37/2Write the equation of a line that passes through the points (-24, 18) and (0, 33)y = 5/8 x + 33

Answer from: Quest

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180° and ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

Answer from: Quest

given : the shape of his satellite can be modeled by where x and y are modeled in inches.

now,the given equation is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation:

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An implicit equation for the plane passing through the point (-1,-4,5) that is perpendicular to the...

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