A, b, and c are polynomials, where a = n, b = 2n + 6, and c = n2 – 1. what is ab – c in simplest form? a=–n2 + 3n + 5 b=n2 + 6n + 1 c=2n2 + 6n – 1 d=3n2 + 5

A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form?      We want (n)(2n+6) - (n^2-1).  (Please note: n^2 is correct, while n2 is not.)

Multiplying out the first term:  2n^2 + 6n 
Subtracting n^2-1:                 - (n^2 -1)
                                             
                                                  n^2 + 6n + 1     (answer) 

Oh i'm sorry. didn't see the options