Mathematics, 19.08.2019 09:30 GreenHerbz206
In rhombus abcd, ab = 13 and ac = 25. find the area of the rhombusto the nearest tenth.
Answers: 1
![the\ area\ of\ the\ rhombus=\\=half\ the\ product\ of\ the\ diagonals\ of\ a\ rhombus\\\\A= \frac{1}{2}\cdot |AB|\cdot |AC|=\frac{1}{2}\cdot 13\cdot 25= 162.5\ [u^2]](/tpl/images/0178/3953/acaef.png)
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In rhombus abcd, ab = 13 and ac = 25. find the area of the rhombusto the nearest tenth....
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