Which quadratic function has a leading coefficient of 2 and a constant term of –3? f(x) = 2x3 – 3 f(x) = –3x2 – 3x + 2 f(x) = –3x3 + 2 f(x) = 2x2 + 3x – 3

From the four functions listed, eliminate the middle two, because neither has the constant coefficient 2.

This leaves f(x) = 2x^3 - 3 and f(x) = 2x^2 + 3x - 3.
Please note:  use "^" to indicate exponentiation; do not write "x2" or "x3."

Eliminate f(x) = 2x^3-3, because it's NOT a quadratic function.

This leaves f(x) = 2x^2 + 3x - 3 as the answer; it has a leading coeff. of 2 and a constant term of -3, as required.