Point a is located at negative 5 over 8 and point b is located at negative 2 over 8. what is the distance between points a and b?

The answer would be Negative 5 over 8 minus negative 2 over 8 = negative 3 over 8 ; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units!

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q