What is the area of a parallelogram whose vertices are a(−1, 12) , b(13, 12) , c(2, −5) , and d(−12, −5) ?

The area of the parallelogram with the given vertices=238 square units.

Step-by-step explanation:

Let CD be the base of the parallelogram ABCD is given by distance formula

CD=units[or you can count distance by using graph as ordinates of C and D are same to we can count the distance of x from C to D]

Now consider P a point on CD such that AP become the height of the parallelogram which is given by (from the graph attached)=17 [as abscissa of P and A are same to we can count the distance of y from A to P]

Area of parallelogram = base × height=14×17=238 square units.

the answer is 0.071

good luck! : d

thats not a system of equations, that is a solution