What is the period, in seconds, of a simple pendulum of length 2 meters? use the gravitational constant g = 9.8 m/s^2 and round your answer to two decimal places.

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

            ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and

Substitute the given values we have;

⇒

Therefore, the period, in seconds to two decimal places is, 2.84 sec

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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